9p^2p=1/3

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Solution for 9p^2p=1/3 equation:



9p^2p=1/3
We move all terms to the left:
9p^2p-(1/3)=0
We add all the numbers together, and all the variables
9p^2p-(+1/3)=0
We get rid of parentheses
9p^2p-1/3=0
We multiply all the terms by the denominator
9p^2p*3-1=0
Wy multiply elements
27p^2-1=0
a = 27; b = 0; c = -1;
Δ = b2-4ac
Δ = 02-4·27·(-1)
Δ = 108
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{108}=\sqrt{36*3}=\sqrt{36}*\sqrt{3}=6\sqrt{3}$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{3}}{2*27}=\frac{0-6\sqrt{3}}{54} =-\frac{6\sqrt{3}}{54} =-\frac{\sqrt{3}}{9} $
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{3}}{2*27}=\frac{0+6\sqrt{3}}{54} =\frac{6\sqrt{3}}{54} =\frac{\sqrt{3}}{9} $

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